StrBuf::Append( const char *, int )

Append a string of a specified length to a StrBuf. The string is logically appended to the string pointed to by the StrBuf's buffer.

Virtual?	No
Class	StrBuf
Arguments	const char *buf	pointer to the first byte of the string
	int len	length of the string
Returns	void

Notes

Exactly len bytes are appended to the StrBuf from the string. The length of the StrBuf is incremented by the len argument.

If the memory for the StrBuf's buffer is not large enough, new memory to contiguously contain the results of appending the string of specified length is allocated. If new memory is allocated, the old memory is freed. Any memory allocated is separate from the memory for the string.

Example

#include <iostream>

#include <stdhdrs.h>
#include <strbuf.h>

int main( int argc, char **argv )
{
    char chars[] = "zyx";
    StrBuf sb;

    sb.Set( "xyz" );

    cout << "sb.Text() prior to sb.Append( chars, 2 ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() prior to sb.Append( chars, 2 ) returns ";
    cout << sb.Length() << "\n\n";

    sb.Append( chars, 2 );   // append len bytes of char * to StrBuf

    cout << "sb.Text() after sb.Append( chars, 2 ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() after sb.Append( chars, 2 ) returns ";
    cout << sb.Length() << "\n";
}

Executing the preceding code produces the following output:

sb.Text() prior to sb.Append( chars, 2 ) returns "xyz"
sb.Length() prior to sb.Append( chars, 2 ) returns 3

sb.Text() after sb.Append( chars, 2 ) returns "xyzzy"
sb.Length() after sb.Append( chars, 2 ) returns 5