StrBuf::Extend( char )

Extend a StrBuf by one byte. The string pointed to by the StrBuf's buffer is logically extended.

Virtual?	No
Class	StrBuf
Arguments	char c	the byte copied to the extended string
Returns	void

Notes

One byte is copied to the extended StrBuf. The length of the StrBuf is incremented by one.

Extend() does not null-terminate the extended string pointed to by the StrBuf's buffer. To ensure that the extended string is null-terminated, call Terminate() after calling Extend().

If the memory for the StrBuf's buffer is not large enough, enough new memory is allocated to contiguously contain the extended string. If new memory is allocated, the old memory is freed. Any memory allocated is separate from the memory for the byte.

See also

StrBuf::Terminate()

Example

#include <iostream>

#include <stdhdrs.h>
#include <strbuf.h>

int main( int argc, char **argv )
{
    StrBuf sb;

    sb.Set( "xy" );

    cout << "sb.Text() prior to sb.Extend( 'z' ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() prior to sb.Extend( 'z' ) returns ";
    cout << sb.Length() << "\n\n";

    sb.Extend( 'z' );   // extend StrBuf from char
    sb.Terminate();

    cout << "sb.Text() after sb.Extend( 'z' ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() after sb.Extend( 'z' ) returns ";
    cout << sb.Length() << "\n";
}

Executing the preceding code produces the following output:

sb.Text() prior to sb.Extend( 'z' ) returns "xy"
sb.Length() prior to sb.Extend( 'z' ) returns 2

sb.Text() after sb.Extend( 'z' ) returns "xyz"
sb.Length() after sb.Extend( 'z' ) returns 3