StrBuf::operator =( const StrBuf & )

Assign a StrBuf from another StrBuf.

Virtual?	No
Class	StrBuf
Arguments	const StrBuf &buf	(implied) reference of the StrBuf from which assignment occurs
Returns	void

Notes

Initialize both StrBufs before the assignment.

Any memory allocated for the assigned StrBuf's buffer is separate from the memory for the StrBuf's buffer from which assignment occurs.

Do not assign a StrBuf to itself.

Example

#include <iostream>

#include <stdhdrs.h>
#include <strbuf.h>

int main( int argc, char **argv )
{
    StrBuf sba;
    StrBuf sbb;

    sba.Set( "xyz" );

    sbb = sba;   // assign StrBuf to StrBuf

    cout << "sba.Text() returns \"" << sba.Text() << "\"\n";
    cout << "sbb.Text() returns \"" << sbb.Text() << "\"\n";
}

Executing the preceding code produces the following output:

sba.Text() returns "xyz"
sbb.Text() returns "xyz"